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Discussion Groups | LPC2000 | interrupts + Keil + LPC2294
Discussion group dedicated to the Philips LPC2000 family of ARM MCUs
interrupts + Keil + LPC2294 - grodo2k - Mar 21 7:38:00 2006
Hello
could someone be so kind and say, what is wrong in following code? Or
maybe it is ok, but it doesn't work... I want trigger an interrupt
using UART0. I am using Keil. (UART0 is ok, it sends a string from tab).
thanks in advance
int i,j;
char tab[] = "UART0 is working properly";
void UART0INT() __irq
{
IO0CLR |= 0x20000; //clr P0.17 (it's a LED)
for(i=0;i<5;i++)
{
for(j=0;j<50000;j++){}
}
send_char_u0('A');
VICVectAddr = 0x00000000; //dummy write
}
int main(void)
{
PLL_ON();
LED_init();
VPBDIV = 0x1;
UART0_init();
IO0SET |= 0x20000; //set P0.17
send_string_u0(tab);
VICIntSelect = 0x00000000;
VICVectAddr0 = (unsigned) UART0INT;
VICVectCntl0 = 0x26; //UART0
VICIntEnable = 0x40; //bit 6 = UART0
while(1)
{
}
return 0;
}
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RE: interrupts + Keil + LPC2294 - Andrew Berney - Mar 21 12:03:00 2006
Hi,
we could do with the function UART0_init from your code, however I suspect
your problem is that you're not reading U0IIR to clear the UART IRQ. You
also have a huge delay inside your IRQ which kind of defeats the point of
using it. Have a look at the description of U0IIR register.
Here is a working example from a 2129 which should work equally well on your
chip with minor modification:
void main(void)
{
// init the serial ports
init_serial();
// main loop
while(1)
{
for(;;);
}
}
void init_serial (void) // Initialize Serial Interface
{
//UART0
VPBDIV = 0x00000001; //Set PClk to 60Mhz
PINSEL0 = 0x00000005; //Enable TxD0, RxD0
U0LCR = 0x00000083; //8 bits, no Parity, 1 Stop bit
U0DLL = 0x00000084; // 9600 Baud Rate @ 60MHz VPB Clock
U0DLM = 0x00000001;
U0LCR = 0x00000003; // DLAB = 0
U0IER = 0x00000001; //enable rx data available interrupt
VICVectCntl1 = 0x00000026;
VICVectAddr1 = (unsigned)uart0_irq;
VICIntEnable |= 0x00000040;
U0FCR = 0x00000001; //Enable FIFO & trigger level to 1 bytes
}
static unsigned int U0IIR_copy;
void uart0_irq(void) __irq
{
//check for a character from the UART0 RX FIFO
if((U0LSR & 0x01) == 0x01) //if there is a character
{
toggle_LED(1); //do this to suit your board
}
//exit ISR
U0IIR_copy = U0IIR;
VICVectAddr = 0x00000000; //dummy write to re-enable interrupt for next
time
}
-----Original Message-----
From: lpc2000@lpc2... [mailto:lpc2000@lpc2...]On Behalf
Of grodo2k
Sent: 21 March 2006 11:38
To: lpc2000@lpc2...
Subject: [lpc2000] interrupts + Keil + LPC2294
Hello
could someone be so kind and say, what is wrong in following code? Or
maybe it is ok, but it doesn't work... I want trigger an interrupt
using UART0. I am using Keil. (UART0 is ok, it sends a string from tab).
thanks in advance
int i,j;
char tab[] = "UART0 is working properly";
void UART0INT() __irq
{
IO0CLR |= 0x20000; //clr P0.17 (it's a LED)
for(i=0;i<5;i++)
{
for(j=0;j<50000;j++){}
}
send_char_u0('A');
VICVectAddr = 0x00000000; //dummy write
}
int main(void)
{
PLL_ON();
LED_init();
VPBDIV = 0x1;
UART0_init();
IO0SET |= 0x20000; //set P0.17
send_string_u0(tab);
VICIntSelect = 0x00000000;
VICVectAddr0 = (unsigned) UART0INT;
VICVectCntl0 = 0x26; //UART0
VICIntEnable = 0x40; //bit 6 = UART0
while(1)
{
}
return 0;
}
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RE: interrupts + Keil + LPC2294 - Grodo Grodo - Mar 21 15:30:00 2006
Thank you, I'll try it and say if it works by me.
Andrew Berney <amb@amb@...> wrote: Hi,
we could do with the function UART0_init from your code, however I suspect
your problem is that you're not reading U0IIR to clear the UART IRQ. You
also have a huge delay inside your IRQ which kind of defeats the point of
using it. Have a look at the description of U0IIR register.
Here is a working example from a 2129 which should work equally well on your
chip with minor modification:
void main(void)
{
// init the serial ports
init_serial();
// main loop
while(1)
{
for(;;);
}
}
void init_serial (void) // Initialize Serial Interface
{
//UART0
VPBDIV = 0x00000001; //Set PClk to 60Mhz
PINSEL0 = 0x00000005; //Enable TxD0, RxD0
U0LCR = 0x00000083; //8 bits, no Parity, 1 Stop bit
U0DLL = 0x00000084; // 9600 Baud Rate @ 60MHz VPB Clock
U0DLM = 0x00000001;
U0LCR = 0x00000003; // DLAB = 0
U0IER = 0x00000001; //enable rx data available interrupt
VICVectCntl1 = 0x00000026;
VICVectAddr1 = (unsigned)uart0_irq;
VICIntEnable |= 0x00000040;
U0FCR = 0x00000001; //Enable FIFO & trigger level to 1 bytes
}
static unsigned int U0IIR_copy;
void uart0_irq(void) __irq
{
//check for a character from the UART0 RX FIFO
if((U0LSR & 0x01) == 0x01) //if there is a character
{
toggle_LED(1); //do this to suit your board
}
//exit ISR
U0IIR_copy = U0IIR;
VICVectAddr = 0x00000000; //dummy write to re-enable interrupt for next
time
}
-----Original Message-----
From: lpc2000@lpc2... [mailto:lpc2000@lpc2...]On Behalf
Of grodo2k
Sent: 21 March 2006 11:38
To: lpc2000@lpc2...
Subject: [lpc2000] interrupts + Keil + LPC2294
Hello
could someone be so kind and say, what is wrong in following code? Or
maybe it is ok, but it doesn't work... I want trigger an interrupt
using UART0. I am using Keil. (UART0 is ok, it sends a string from tab).
thanks in advance
int i,j;
char tab[] = "UART0 is working properly";
void UART0INT() __irq
{
IO0CLR |= 0x20000; //clr P0.17 (it's a LED)
for(i=0;i<5;i++)
{
for(j=0;j<50000;j++){}
}
send_char_u0('A');
VICVectAddr = 0x00000000; //dummy write
}
int main(void)
{
PLL_ON();
LED_init();
VPBDIV = 0x1;
UART0_init();
IO0SET |= 0x20000; //set P0.17
send_string_u0(tab);
VICIntSelect = 0x00000000;
VICVectAddr0 = (unsigned) UART0INT;
VICVectCntl0 = 0x26; //UART0
VICIntEnable = 0x40; //bit 6 = UART0
while(1)
{
}
return 0;
}
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RE: interrupts + Keil + LPC2294 - Grodo Grodo - Mar 26 7:39:00 2006
Andrew, thank you very much ;) In fact I am working with CrossWorks but I coudn't
trigger any interrupt there, so I thought, maybe I will do it in Keil. But it didn't work
either. Now it is working ;) It helped me much, thanks again ;)
Grodo Grodo <grodo2k@grod...> wrote: Thank you, I'll try it and say if it
works by me.
Andrew Berney <amb@amb@...> wrote: Hi,
we could do with the function UART0_init from your code, however I suspect
your problem is that you're not reading U0IIR to clear the UART IRQ. You
also have a huge delay inside your IRQ which kind of defeats the point of
using it. Have a look at the description of U0IIR register.
Here is a working example from a 2129 which should work equally well on your
chip with minor modification:
void main(void)
{
// init the serial ports
init_serial();
// main loop
while(1)
{
for(;;);
}
}
void init_serial (void) // Initialize Serial Interface
{
//UART0
VPBDIV = 0x00000001; //Set PClk to 60Mhz
PINSEL0 = 0x00000005; //Enable TxD0, RxD0
U0LCR = 0x00000083; //8 bits, no Parity, 1 Stop bit
U0DLL = 0x00000084; // 9600 Baud Rate @ 60MHz VPB Clock
U0DLM = 0x00000001;
U0LCR = 0x00000003; // DLAB = 0
U0IER = 0x00000001; //enable rx data available interrupt
VICVectCntl1 = 0x00000026;
VICVectAddr1 = (unsigned)uart0_irq;
VICIntEnable |= 0x00000040;
U0FCR = 0x00000001; //Enable FIFO & trigger level to 1 bytes
}
static unsigned int U0IIR_copy;
void uart0_irq(void) __irq
{
//check for a character from the UART0 RX FIFO
if((U0LSR & 0x01) == 0x01) //if there is a character
{
toggle_LED(1); //do this to suit your board
}
//exit ISR
U0IIR_copy = U0IIR;
VICVectAddr = 0x00000000; //dummy write to re-enable interrupt for next
time
}
-----Original Message-----
From: lpc2000@lpc2... [mailto:lpc2000@lpc2...]On Behalf
Of grodo2k
Sent: 21 March 2006 11:38
To: lpc2000@lpc2...
Subject: [lpc2000] interrupts + Keil + LPC2294
Hello
could someone be so kind and say, what is wrong in following code? Or
maybe it is ok, but it doesn't work... I want trigger an interrupt
using UART0. I am using Keil. (UART0 is ok, it sends a string from tab).
thanks in advance
int i,j;
char tab[] = "UART0 is working properly";
void UART0INT() __irq
{
IO0CLR |= 0x20000; //clr P0.17 (it's a LED)
for(i=0;i<5;i++)
{
for(j=0;j<50000;j++){}
}
send_char_u0('A');
VICVectAddr = 0x00000000; //dummy write
}
int main(void)
{
PLL_ON();
LED_init();
VPBDIV = 0x1;
UART0_init();
IO0SET |= 0x20000; //set P0.17
send_string_u0(tab);
VICIntSelect = 0x00000000;
VICVectAddr0 = (unsigned) UART0INT;
VICVectCntl0 = 0x26; //UART0
VICIntEnable = 0x40; //bit 6 = UART0
while(1)
{
}
return 0;
}
Yahoo! Groups Links
SPONSORED LINKS
Microcontrollers
Microprocessor Intel
microprocessors
Pic microcontrollers
---------------------------------
YAHOO! GROUPS LINKS
---------------------------------
---------------------------------
Yahoo! Travel
Find great deals to the top 10 hottest destinations!
[Non-text portions of this message have been removed]
SPONSORED LINKS
Microcontrollers
Microprocessor Intel
microprocessors
Pic microcontrollers
---------------------------------
YAHOO! GROUPS LINKS
---------------------------------
---------------------------------
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